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134223103141 = 679119764851
BaseRepresentation
bin111110100000001010…
…0100000010010100101
3110211110020110010001021
41331000110200102211
54144342103300031
6141354454531141
712461113360261
oct1750024402245
9424406403037
10134223103141
1151a18496016
122201b066ab1
13c870aac22a
1466d42d70a1
1537589a8511
hex1f405204a5

134223103141 has 4 divisors (see below), whose sum is σ = 134242874784. Its totient is φ = 134203331500.

The previous prime is 134223103129. The next prime is 134223103199. The reversal of 134223103141 is 141301322431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 141301322431 = 395033576977.

It is a cyclic number.

It is not a de Polignac number, because 134223103141 - 25 = 134223103109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134223103541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9875635 + ... + 9889216.

It is an arithmetic number, because the mean of its divisors is an integer number (33560718696).

Almost surely, 2134223103141 is an apocalyptic number.

It is an amenable number.

134223103141 is a deficient number, since it is larger than the sum of its proper divisors (19771643).

134223103141 is an equidigital number, since it uses as much as digits as its factorization.

134223103141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19771642.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 134223103141 its reverse (141301322431), we get a palindrome (275524425572).

The spelling of 134223103141 in words is "one hundred thirty-four billion, two hundred twenty-three million, one hundred three thousand, one hundred forty-one".

Divisors: 1 6791 19764851 134223103141