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134223433 is a prime number
BaseRepresentation
bin10000000000000…
…01011001001001
3100100120020221021
420000001121021
5233330122213
621152512441
73216610651
oct1000013111
9310506837
10134223433
1169847063
1238b4b721
1321a66c66
1413b7d361
15bbb4d8d
hex8001649

134223433 has 2 divisors, whose sum is σ = 134223434. Its totient is φ = 134223432.

The previous prime is 134223431. The next prime is 134223437. The reversal of 134223433 is 334322431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82210489 + 52012944 = 9067^2 + 7212^2 .

It is a cyclic number.

It is not a de Polignac number, because 134223433 - 21 = 134223431 is a prime.

Together with 134223431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 134223398 and 134223407.

It is not a weakly prime, because it can be changed into another prime (134223431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67111716 + 67111717.

It is an arithmetic number, because the mean of its divisors is an integer number (67111717).

Almost surely, 2134223433 is an apocalyptic number.

It is an amenable number.

134223433 is a deficient number, since it is larger than the sum of its proper divisors (1).

134223433 is an equidigital number, since it uses as much as digits as its factorization.

134223433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 25.

The square root of 134223433 is about 11585.4837188613. The cubic root of 134223433 is about 512.0072541799.

Adding to 134223433 its reverse (334322431), we get a palindrome (468545864).

The spelling of 134223433 in words is "one hundred thirty-four million, two hundred twenty-three thousand, four hundred thirty-three".