Base | Representation |
---|---|
bin | 1100001101010010010111… |
… | …0001010000000011101001 |
3 | 1202112011120120210101202201 |
4 | 3003110211301100003221 |
5 | 3224403042023432232 |
6 | 44314100213100201 |
7 | 2553510513341434 |
oct | 303244561200351 |
9 | 52464516711681 |
10 | 13422406467817 |
11 | 4305457590a96 |
12 | 1609428927661 |
13 | 76495c412c29 |
14 | 34590dd3481b |
15 | 1842331edbe7 |
hex | c3525c500e9 |
13422406467817 has 2 divisors, whose sum is σ = 13422406467818. Its totient is φ = 13422406467816.
The previous prime is 13422406467809. The next prime is 13422406467853. The reversal of 13422406467817 is 71876460422431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11082314238121 + 2340092229696 = 3329011^2 + 1529736^2 .
It is a cyclic number.
It is not a de Polignac number, because 13422406467817 - 23 = 13422406467809 is a prime.
It is not a weakly prime, because it can be changed into another prime (13422406467857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711203233908 + 6711203233909.
It is an arithmetic number, because the mean of its divisors is an integer number (6711203233909).
Almost surely, 213422406467817 is an apocalyptic number.
It is an amenable number.
13422406467817 is a deficient number, since it is larger than the sum of its proper divisors (1).
13422406467817 is an equidigital number, since it uses as much as digits as its factorization.
13422406467817 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10838016, while the sum is 55.
The spelling of 13422406467817 in words is "thirteen trillion, four hundred twenty-two billion, four hundred six million, four hundred sixty-seven thousand, eight hundred seventeen".
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