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1342241532532 = 22743834511251
BaseRepresentation
bin10011100010000011110…
…101000110101001110100
311202022120010020122022001
4103202003311012221310
5133442402313020112
62504341154145044
7165654665531425
oct23420365065164
94668503218261
101342241532532
1147827239785a
12198175b82184
139975a6905c4
1448d7172564c
1524dac5cec57
hex13883d46a74

1342241532532 has 12 divisors (see below), whose sum is σ = 2348954781376. Its totient is φ = 671111595000.

The previous prime is 1342241532529. The next prime is 1342241532547. The reversal of 1342241532532 is 2352351422431.

It is a super-2 number, since 2×13422415325322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1342241532491 and 1342241532500.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1958094 + ... + 2553157.

Almost surely, 21342241532532 is an apocalyptic number.

It is an amenable number.

1342241532532 is a deficient number, since it is larger than the sum of its proper divisors (1006713248844).

1342241532532 is a wasteful number, since it uses less digits than its factorization.

1342241532532 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4585638 (or 4585636 counting only the distinct ones).

The product of its digits is 172800, while the sum is 37.

Adding to 1342241532532 its reverse (2352351422431), we get a palindrome (3694592954963).

The spelling of 1342241532532 in words is "one trillion, three hundred forty-two billion, two hundred forty-one million, five hundred thirty-two thousand, five hundred thirty-two".

Divisors: 1 2 4 74383 148766 297532 4511251 9022502 18045004 335560383133 671120766266 1342241532532