Base | Representation |
---|---|
bin | 10011100010000100011… |
… | …001001111010110001011 |
3 | 11202022120210001220112011 |
4 | 103202010121033112023 |
5 | 133442412224132243 |
6 | 2504342133200351 |
7 | 165655142204044 |
oct | 23420431172613 |
9 | 4668523056464 |
10 | 1342251005323 |
11 | 478277777908 |
12 | 1981791900b7 |
13 | 9975c6291c7 |
14 | 48d72aad8cb |
15 | 24dad35189d |
hex | 1388464f58b |
1342251005323 has 2 divisors, whose sum is σ = 1342251005324. Its totient is φ = 1342251005322.
The previous prime is 1342251005321. The next prime is 1342251005357. The reversal of 1342251005323 is 3235001522431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1342251005323 - 21 = 1342251005321 is a prime.
It is a super-2 number, since 2×13422510053232 (a number of 25 digits) contains 22 as substring.
Together with 1342251005321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1342251005321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671125502661 + 671125502662.
It is an arithmetic number, because the mean of its divisors is an integer number (671125502662).
Almost surely, 21342251005323 is an apocalyptic number.
1342251005323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342251005323 is an equidigital number, since it uses as much as digits as its factorization.
1342251005323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 1342251005323 its reverse (3235001522431), we get a palindrome (4577252527754).
The spelling of 1342251005323 in words is "one trillion, three hundred forty-two billion, two hundred fifty-one million, five thousand, three hundred twenty-three".
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