Base | Representation |
---|---|
bin | 10011100010000101010… |
… | …000001001110000010101 |
3 | 11202022121210011020202222 |
4 | 103202011100021300111 |
5 | 133442424420302331 |
6 | 2504343405512125 |
7 | 165655405440035 |
oct | 23420520116025 |
9 | 4668553136688 |
10 | 1342265400341 |
11 | 47828490a018 |
12 | 198181b72645 |
13 | 997625c9378 |
14 | 48d749798c5 |
15 | 24dae746b7b |
hex | 13885409c15 |
1342265400341 has 2 divisors, whose sum is σ = 1342265400342. Its totient is φ = 1342265400340.
The previous prime is 1342265400169. The next prime is 1342265400349. The reversal of 1342265400341 is 1430045622431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1316861822116 + 25403578225 = 1147546^2 + 159385^2 .
It is a cyclic number.
It is not a de Polignac number, because 1342265400341 - 230 = 1341191658517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342265400349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671132700170 + 671132700171.
It is an arithmetic number, because the mean of its divisors is an integer number (671132700171).
Almost surely, 21342265400341 is an apocalyptic number.
It is an amenable number.
1342265400341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342265400341 is an equidigital number, since it uses as much as digits as its factorization.
1342265400341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 35.
The spelling of 1342265400341 in words is "one trillion, three hundred forty-two billion, two hundred sixty-five million, four hundred thousand, three hundred forty-one".
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