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1342301032315 = 5268460206463
BaseRepresentation
bin10011100010000111011…
…000000100111101111011
311202022201021012112122201
4103202013120010331323
5133443013031013230
62504351121331031
7165656320343245
oct23420730047573
94668637175581
101342301032315
114782a2a36931
12198191a96a77
1399769ac3989
1448d795b3095
1524db29345ca
hex13887604f7b

1342301032315 has 4 divisors (see below), whose sum is σ = 1610761238784. Its totient is φ = 1073840825848.

The previous prime is 1342301032283. The next prime is 1342301032349. The reversal of 1342301032315 is 5132301032431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1342301032315 - 25 = 1342301032283 is a prime.

It is a super-2 number, since 2×13423010323152 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134230103227 + ... + 134230103236.

It is an arithmetic number, because the mean of its divisors is an integer number (402690309696).

Almost surely, 21342301032315 is an apocalyptic number.

1342301032315 is a deficient number, since it is larger than the sum of its proper divisors (268460206469).

1342301032315 is an equidigital number, since it uses as much as digits as its factorization.

1342301032315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 268460206468.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 1342301032315 its reverse (5132301032431), we get a palindrome (6474602064746).

The spelling of 1342301032315 in words is "one trillion, three hundred forty-two billion, three hundred one million, thirty-two thousand, three hundred fifteen".

Divisors: 1 5 268460206463 1342301032315