Base | Representation |
---|---|
bin | 10011100010000111111… |
… | …010101100000001000001 |
3 | 11202022201220021111020202 |
4 | 103202013322230001001 |
5 | 133443022341331103 |
6 | 2504352044014545 |
7 | 165656460431543 |
oct | 23420772540101 |
9 | 4668656244222 |
10 | 1342310105153 |
11 | 4782a8073446 |
12 | 198194b31455 |
13 | 9976b94c514 |
14 | 48d7a895693 |
15 | 24db3627988 |
hex | 13887eac041 |
1342310105153 has 2 divisors, whose sum is σ = 1342310105154. Its totient is φ = 1342310105152.
The previous prime is 1342310105113. The next prime is 1342310105197. The reversal of 1342310105153 is 3515010132431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1037896387984 + 304413717169 = 1018772^2 + 551737^2 .
It is a cyclic number.
It is not a de Polignac number, because 1342310105153 - 26 = 1342310105089 is a prime.
It is not a weakly prime, because it can be changed into another prime (1342310105113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671155052576 + 671155052577.
It is an arithmetic number, because the mean of its divisors is an integer number (671155052577).
Almost surely, 21342310105153 is an apocalyptic number.
It is an amenable number.
1342310105153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342310105153 is an equidigital number, since it uses as much as digits as its factorization.
1342310105153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 1342310105153 its reverse (3515010132431), we get a palindrome (4857320237584).
The spelling of 1342310105153 in words is "one trillion, three hundred forty-two billion, three hundred ten million, one hundred five thousand, one hundred fifty-three".
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