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1342311026993 is a prime number
BaseRepresentation
bin10011100010000111111…
…110001101000100110001
311202022201222000022202222
4103202013332031010301
5133443023110330433
62504352115450425
7165656501321246
oct23420776150461
94668658008688
101342311026993
114782a8642aa2
121981952b6a15
139976bbb2ca1
1448d7aa555cd
1524db375ab98
hex13887f8d131

1342311026993 has 2 divisors, whose sum is σ = 1342311026994. Its totient is φ = 1342311026992.

The previous prime is 1342311026971. The next prime is 1342311027037. The reversal of 1342311026993 is 3996201132431.

It is an a-pointer prime, because the next prime (1342311027037) can be obtained adding 1342311026993 to its sum of digits (44).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1217509214464 + 124801812529 = 1103408^2 + 353273^2 .

It is a cyclic number.

It is not a de Polignac number, because 1342311026993 - 214 = 1342311010609 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1342311026933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671155513496 + 671155513497.

It is an arithmetic number, because the mean of its divisors is an integer number (671155513497).

Almost surely, 21342311026993 is an apocalyptic number.

It is an amenable number.

1342311026993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342311026993 is an equidigital number, since it uses as much as digits as its factorization.

1342311026993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 209952, while the sum is 44.

The spelling of 1342311026993 in words is "one trillion, three hundred forty-two billion, three hundred eleven million, twenty-six thousand, nine hundred ninety-three".