Base | Representation |
---|---|
bin | 10011100010000111111… |
… | …110001111001001010101 |
3 | 11202022201222000202102012 |
4 | 103202013332033021111 |
5 | 133443023111113402 |
6 | 2504352115554005 |
7 | 165656501355056 |
oct | 23420776171125 |
9 | 4668658022365 |
10 | 1342311035477 |
11 | 4782a8649405 |
12 | 1981952bb905 |
13 | 9976bbb6ac9 |
14 | 48d7aa5872d |
15 | 24db375d452 |
hex | 13887f8f255 |
1342311035477 has 2 divisors, whose sum is σ = 1342311035478. Its totient is φ = 1342311035476.
The previous prime is 1342311035453. The next prime is 1342311035491. The reversal of 1342311035477 is 7745301132431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1316272049521 + 26038985956 = 1147289^2 + 161366^2 .
It is an emirp because it is prime and its reverse (7745301132431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1342311035477 - 210 = 1342311034453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342311035437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671155517738 + 671155517739.
It is an arithmetic number, because the mean of its divisors is an integer number (671155517739).
Almost surely, 21342311035477 is an apocalyptic number.
It is an amenable number.
1342311035477 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342311035477 is an equidigital number, since it uses as much as digits as its factorization.
1342311035477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 211680, while the sum is 41.
The spelling of 1342311035477 in words is "one trillion, three hundred forty-two billion, three hundred eleven million, thirty-five thousand, four hundred seventy-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •