Base | Representation |
---|---|
bin | 1100001101010101111001… |
… | …0101001111110100010101 |
3 | 1202112021000201102120120111 |
4 | 3003111132111033310111 |
5 | 3224412012442144432 |
6 | 44314334312403021 |
7 | 2553543155354515 |
oct | 303253625176425 |
9 | 52467021376514 |
10 | 13423355428117 |
11 | 43058a42139a8 |
12 | 16096526a6471 |
13 | 764a80bbc6bb |
14 | 34599dd97845 |
15 | 18428b69c347 |
hex | c355e54fd15 |
13423355428117 has 2 divisors, whose sum is σ = 13423355428118. Its totient is φ = 13423355428116.
The previous prime is 13423355428097. The next prime is 13423355428141. The reversal of 13423355428117 is 71182455332431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13422030904881 + 1324523236 = 3663609^2 + 36394^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13423355428117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13423355423117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711677714058 + 6711677714059.
It is an arithmetic number, because the mean of its divisors is an integer number (6711677714059).
Almost surely, 213423355428117 is an apocalyptic number.
It is an amenable number.
13423355428117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13423355428117 is an equidigital number, since it uses as much as digits as its factorization.
13423355428117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2419200, while the sum is 49.
The spelling of 13423355428117 in words is "thirteen trillion, four hundred twenty-three billion, three hundred fifty-five million, four hundred twenty-eight thousand, one hundred seventeen".
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