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13423397329889 is a prime number
BaseRepresentation
bin1100001101010110000011…
…0101000101101111100001
31202112021010122021101222222
43003111200311011233201
53224412104204024024
644314342410440425
72553544204463231
oct303254065055741
952467118241888
1013423397329889
114305915933368
121609664733115
13764a897a0a51
143459a5783cc1
151842901c785e
hexc3560d45be1

13423397329889 has 2 divisors, whose sum is σ = 13423397329890. Its totient is φ = 13423397329888.

The previous prime is 13423397329831. The next prime is 13423397329891. The reversal of 13423397329889 is 98892379332431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10137091854400 + 3286305475489 = 3183880^2 + 1812817^2 .

It is a cyclic number.

It is not a de Polignac number, because 13423397329889 - 216 = 13423397264353 is a prime.

It is a super-2 number, since 2×134233973298892 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13423397329891, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13423397325889) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711698664944 + 6711698664945.

It is an arithmetic number, because the mean of its divisors is an integer number (6711698664945).

Almost surely, 213423397329889 is an apocalyptic number.

It is an amenable number.

13423397329889 is a deficient number, since it is larger than the sum of its proper divisors (1).

13423397329889 is an equidigital number, since it uses as much as digits as its factorization.

13423397329889 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 423263232, while the sum is 71.

The spelling of 13423397329889 in words is "thirteen trillion, four hundred twenty-three billion, three hundred ninety-seven million, three hundred twenty-nine thousand, eight hundred eighty-nine".