13423445224555 has 4 divisors (see below), whose sum is σ = 16108134269472. Its totient is φ = 10738756179640.

The previous prime is 13423445224531. The next prime is 13423445224601. The reversal of 13423445224555 is 55542254432431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13423445224555 - 2⁹ = 13423445224043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13423445224499 and 13423445224508.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1342344522451 + ... + 1342344522460.

It is an arithmetic number, because the mean of its divisors is an integer number (4027033567368).

Almost surely, 2^{13423445224555} is an apocalyptic number.

13423445224555 is a deficient number, since it is larger than the sum of its proper divisors (2684689044917).

13423445224555 is an equidigital number, since it uses as much as digits as its factorization.

13423445224555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2684689044916.

The product of its digits is 11520000, while the sum is 49.

Adding to 13423445224555 its reverse (55542254432431), we get a palindrome (68965699656986).

The spelling of 13423445224555 in words is "thirteen trillion, four hundred twenty-three billion, four hundred forty-five million, two hundred twenty-four thousand, five hundred fifty-five".