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134234534240000 = 28544717850337
BaseRepresentation
bin11110100001010111101001…
…101110101101111100000000
3122121021200210111020211112022
4132201113221232231330000
5120043244311231140000
61153254254350421012
740163060615646215
oct3641275156557400
9577250714224468
10134234534240000
1139853601100707
121307b675b01768
1359b935426950c
142520db3cc7b0c
15107bb35705585
hex7a15e9badf00

134234534240000 has 180 divisors, whose sum is σ = 341947643652384. Its totient is φ = 52551389184000.

The previous prime is 134234534239999. The next prime is 134234534240033. The reversal of 134234534240000 is 42435432431.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 1405169 + ... + 16445168.

Almost surely, 2134234534240000 is an apocalyptic number.

134234534240000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134234534240000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170973821826192).

134234534240000 is an abundant number, since it is smaller than the sum of its proper divisors (207713109412384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134234534240000 is an frugal number, since it uses more digits than its factorization.

134234534240000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17850420 (or 17850391 counting only the distinct ones).

The product of its (nonzero) digits is 138240, while the sum is 35.

Adding to 134234534240000 its reverse (42435432431), we get a palindrome (134276969672431).

The spelling of 134234534240000 in words is "one hundred thirty-four trillion, two hundred thirty-four billion, five hundred thirty-four million, two hundred forty thousand".