13423544241035 has 4 divisors (see below), whose sum is σ = 16108253089248. Its totient is φ = 10738835392824.

The previous prime is 13423544241011. The next prime is 13423544241091. The reversal of 13423544241035 is 53014244532431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13423544241035 - 2¹² = 13423544236939 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13423544240983 and 13423544241001.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1342354424099 + ... + 1342354424108.

It is an arithmetic number, because the mean of its divisors is an integer number (4027063272312).

Almost surely, 2^{13423544241035} is an apocalyptic number.

13423544241035 is a deficient number, since it is larger than the sum of its proper divisors (2684708848213).

13423544241035 is an equidigital number, since it uses as much as digits as its factorization.

13423544241035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2684708848212.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 13423544241035 its reverse (53014244532431), we get a palindrome (66437788773466).

The spelling of 13423544241035 in words is "thirteen trillion, four hundred twenty-three billion, five hundred forty-four million, two hundred forty-one thousand, thirty-five".