Base | Representation |
---|---|
bin | 11110100001011100111101… |
… | …011010101001001111001111 |
3 | 122121022020111122220120220120 |
4 | 132201130331122221033033 |
5 | 120043342444201400221 |
6 | 1153301040051520023 |
7 | 40163352056404224 |
oct | 3641347532511717 |
9 | 577266448816816 |
10 | 134240233231311 |
11 | 39855a66029189 |
12 | 130807a65b9013 |
13 | 59b9a51b7331c |
14 | 2521394b3d94b |
15 | 107bd6abd05c6 |
hex | 7a173d6a93cf |
134240233231311 has 4 divisors (see below), whose sum is σ = 178986977641752. Its totient is φ = 89493488820872.
The previous prime is 134240233231301. The next prime is 134240233231331. The reversal of 134240233231311 is 113132332042431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134240233231311 - 215 = 134240233198543 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134240233231301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22373372205216 + ... + 22373372205221.
It is an arithmetic number, because the mean of its divisors is an integer number (44746744410438).
Almost surely, 2134240233231311 is an apocalyptic number.
134240233231311 is a deficient number, since it is larger than the sum of its proper divisors (44746744410441).
134240233231311 is an equidigital number, since it uses as much as digits as its factorization.
134240233231311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44746744410440.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 134240233231311 its reverse (113132332042431), we get a palindrome (247372565273742).
The spelling of 134240233231311 in words is "one hundred thirty-four trillion, two hundred forty billion, two hundred thirty-three million, two hundred thirty-one thousand, three hundred eleven".
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