1342412113 has 4 divisors (see below), whose sum is σ = 1534185280. Its totient is φ = 1150638948.

The previous prime is 1342412107. The next prime is 1342412179. The reversal of 1342412113 is 3112142431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112142431 = 743 ⋅4188617.

It is a cyclic number.

It is not a de Polignac number, because 1342412113 - 2¹³ = 1342403921 is a prime.

It is a super-2 number, since 2×1342412113² = 3604140562258249538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1342418113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95886573 + ... + 95886586.

It is an arithmetic number, because the mean of its divisors is an integer number (383546320).

Almost surely, 2^1342412113 is an apocalyptic number.

It is an amenable number.

1342412113 is a deficient number, since it is larger than the sum of its proper divisors (191773167).

1342412113 is an equidigital number, since it uses as much as digits as its factorization.

1342412113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191773166.

The product of its digits is 576, while the sum is 22.

The square root of 1342412113 is about 36638.9425748069. The cubic root of 1342412113 is about 1103.1348901713.

Adding to 1342412113 its reverse (3112142431), we get a palindrome (4454554544).

The spelling of 1342412113 in words is "one billion, three hundred forty-two million, four hundred twelve thousand, one hundred thirteen".