Base | Representation |
---|---|
bin | 10011100010001110001… |
… | …000001101011111000101 |
3 | 11202100000011100211002221 |
4 | 103202032020031133011 |
5 | 133443231031012123 |
6 | 2504410245332341 |
7 | 165662164251655 |
oct | 23421610153705 |
9 | 4670004324087 |
10 | 1342414313413 |
11 | 478350979678 |
12 | 198203a070b1 |
13 | 99787407604 |
14 | 48d8a660365 |
15 | 24dbc85e25d |
hex | 1388e20d7c5 |
1342414313413 has 2 divisors, whose sum is σ = 1342414313414. Its totient is φ = 1342414313412.
The previous prime is 1342414313389. The next prime is 1342414313419. The reversal of 1342414313413 is 3143134142431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1198232351044 + 144181962369 = 1094638^2 + 379713^2 .
It is a cyclic number.
It is not a de Polignac number, because 1342414313413 - 237 = 1204975359941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342414313419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671207156706 + 671207156707.
It is an arithmetic number, because the mean of its divisors is an integer number (671207156707).
Almost surely, 21342414313413 is an apocalyptic number.
It is an amenable number.
1342414313413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342414313413 is an equidigital number, since it uses as much as digits as its factorization.
1342414313413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41472, while the sum is 34.
Adding to 1342414313413 its reverse (3143134142431), we get a palindrome (4485548455844).
The spelling of 1342414313413 in words is "one trillion, three hundred forty-two billion, four hundred fourteen million, three hundred thirteen thousand, four hundred thirteen".
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