1342423112433 has 8 divisors (see below), whose sum is σ = 1927581905088. Its totient is φ = 826106530704.

The previous prime is 1342423112423. The next prime is 1342423112447. The reversal of 1342423112433 is 3342113242431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-1342423112433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1342423112394 and 1342423112403.

It is not an unprimeable number, because it can be changed into a prime (1342423112423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17210552685 + ... + 17210552762.

It is an arithmetic number, because the mean of its divisors is an integer number (240947738136).

Almost surely, 2^{1342423112433} is an apocalyptic number.

1342423112433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1342423112433 is a deficient number, since it is larger than the sum of its proper divisors (585158792655).

1342423112433 is a wasteful number, since it uses less digits than its factorization.

1342423112433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34421105463.

The product of its digits is 41472, while the sum is 33.

Adding to 1342423112433 its reverse (3342113242431), we get a palindrome (4684536354864).

The spelling of 1342423112433 in words is "one trillion, three hundred forty-two billion, four hundred twenty-three million, one hundred twelve thousand, four hundred thirty-three".