13424403433 has 6 divisors (see below), whose sum is σ = 15616142826. Its totient is φ = 11506631472.

The previous prime is 13424403409. The next prime is 13424403439. The reversal of 13424403433 is 33430442431.

It can be written as a sum of positive squares in only one way, i.e., 11773769049 + 1650634384 = 108507^2 + 40628^2 .

It is not a de Polignac number, because 13424403433 - 2⁹ = 13424402921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13424403395 and 13424403404.

It is not an unprimeable number, because it can be changed into a prime (13424403439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 136983660 + ... + 136983757.

It is an arithmetic number, because the mean of its divisors is an integer number (2602690471).

Almost surely, 2^13424403433 is an apocalyptic number.

It is an amenable number.

13424403433 is a deficient number, since it is larger than the sum of its proper divisors (2191739393).

13424403433 is an equidigital number, since it uses as much as digits as its factorization.

13424403433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 273967431 (or 273967424 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 13424403433 its reverse (33430442431), we get a palindrome (46854845864).

The spelling of 13424403433 in words is "thirteen billion, four hundred twenty-four million, four hundred three thousand, four hundred thirty-three".