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13424425325561 is a prime number
BaseRepresentation
bin1100001101011001111000…
…0110100101001111111001
31202112100210021121222221202
43003112132012211033321
53224421210340404221
644315032412143545
72553611526344165
oct303263606451771
952470707558852
1013424425325561
1143062a3138768
1216098b0a67bb5
13764bc1760803
14345a620dbca5
15184300588d0b
hexc359e1a53f9

13424425325561 has 2 divisors, whose sum is σ = 13424425325562. Its totient is φ = 13424425325560.

The previous prime is 13424425325551. The next prime is 13424425325603. The reversal of 13424425325561 is 16552352442431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12604232459536 + 820192866025 = 3550244^2 + 905645^2 .

It is a cyclic number.

It is not a de Polignac number, because 13424425325561 - 210 = 13424425324537 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13424425325551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712212662780 + 6712212662781.

It is an arithmetic number, because the mean of its divisors is an integer number (6712212662781).

Almost surely, 213424425325561 is an apocalyptic number.

It is an amenable number.

13424425325561 is a deficient number, since it is larger than the sum of its proper divisors (1).

13424425325561 is an equidigital number, since it uses as much as digits as its factorization.

13424425325561 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3456000, while the sum is 47.

Adding to 13424425325561 its reverse (16552352442431), we get a palindrome (29976777767992).

The spelling of 13424425325561 in words is "thirteen trillion, four hundred twenty-four billion, four hundred twenty-five million, three hundred twenty-five thousand, five hundred sixty-one".