Base | Representation |
---|---|
bin | 1100001101011001111000… |
… | …0110100101001111101111 |
3 | 1202112100210021121222221101 |
4 | 3003112132012211033233 |
5 | 3224421210340404201 |
6 | 44315032412143531 |
7 | 2553611526344152 |
oct | 303263606451757 |
9 | 52470707558841 |
10 | 13424425325551 |
11 | 43062a3138759 |
12 | 16098b0a67ba7 |
13 | 764bc17607c6 |
14 | 345a620dbc99 |
15 | 184300588d01 |
hex | c359e1a53ef |
13424425325551 has 2 divisors, whose sum is σ = 13424425325552. Its totient is φ = 13424425325550.
The previous prime is 13424425325449. The next prime is 13424425325561. The reversal of 13424425325551 is 15552352442431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13424425325551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13424425325561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712212662775 + 6712212662776.
It is an arithmetic number, because the mean of its divisors is an integer number (6712212662776).
Almost surely, 213424425325551 is an apocalyptic number.
13424425325551 is a deficient number, since it is larger than the sum of its proper divisors (1).
13424425325551 is an equidigital number, since it uses as much as digits as its factorization.
13424425325551 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2880000, while the sum is 46.
Adding to 13424425325551 its reverse (15552352442431), we get a palindrome (28976777767982).
The spelling of 13424425325551 in words is "thirteen trillion, four hundred twenty-four billion, four hundred twenty-five million, three hundred twenty-five thousand, five hundred fifty-one".
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