Base | Representation |
---|---|
bin | 1100001101011001111001… |
… | …1100010001100100100011 |
3 | 1202112100210200022220110110 |
4 | 3003112132130101210203 |
5 | 3224421213314342011 |
6 | 44315033134102403 |
7 | 2553611625600126 |
oct | 303263634214443 |
9 | 52470720286413 |
10 | 13424431012131 |
11 | 43062a6372107 |
12 | 16098b294aa03 |
13 | 764bc29a1c49 |
14 | 345a62b7c3bd |
15 | 184300d0dba6 |
hex | c359e711923 |
13424431012131 has 4 divisors (see below), whose sum is σ = 17899241349512. Its totient is φ = 8949620674752.
The previous prime is 13424431012129. The next prime is 13424431012147. The reversal of 13424431012131 is 13121013442431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13424431012131 - 21 = 13424431012129 is a prime.
It is a super-2 number, since 2×134244310121312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13424431012151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2237405168686 + ... + 2237405168691.
It is an arithmetic number, because the mean of its divisors is an integer number (4474810337378).
Almost surely, 213424431012131 is an apocalyptic number.
13424431012131 is a deficient number, since it is larger than the sum of its proper divisors (4474810337381).
13424431012131 is an equidigital number, since it uses as much as digits as its factorization.
13424431012131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4474810337380.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 13424431012131 its reverse (13121013442431), we get a palindrome (26545444454562).
The spelling of 13424431012131 in words is "thirteen trillion, four hundred twenty-four billion, four hundred thirty-one million, twelve thousand, one hundred thirty-one".
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