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13424431012131 = 34474810337377
BaseRepresentation
bin1100001101011001111001…
…1100010001100100100011
31202112100210200022220110110
43003112132130101210203
53224421213314342011
644315033134102403
72553611625600126
oct303263634214443
952470720286413
1013424431012131
1143062a6372107
1216098b294aa03
13764bc29a1c49
14345a62b7c3bd
15184300d0dba6
hexc359e711923

13424431012131 has 4 divisors (see below), whose sum is σ = 17899241349512. Its totient is φ = 8949620674752.

The previous prime is 13424431012129. The next prime is 13424431012147. The reversal of 13424431012131 is 13121013442431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13424431012131 - 21 = 13424431012129 is a prime.

It is a super-2 number, since 2×134244310121312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13424431012151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2237405168686 + ... + 2237405168691.

It is an arithmetic number, because the mean of its divisors is an integer number (4474810337378).

Almost surely, 213424431012131 is an apocalyptic number.

13424431012131 is a deficient number, since it is larger than the sum of its proper divisors (4474810337381).

13424431012131 is an equidigital number, since it uses as much as digits as its factorization.

13424431012131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4474810337380.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 13424431012131 its reverse (13121013442431), we get a palindrome (26545444454562).

The spelling of 13424431012131 in words is "thirteen trillion, four hundred twenty-four billion, four hundred thirty-one million, twelve thousand, one hundred thirty-one".

Divisors: 1 3 4474810337377 13424431012131