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13424434020254 = 226592524338853
BaseRepresentation
bin1100001101011001111010…
…0111101111111110011110
31202112100210212222201211102
43003112132213233332132
53224421220102122004
644315033322353102
72553611663266145
oct303263647577636
952470725881742
1013424434020254
1143062a8037164
1216098b395b792
13764bc34b61ba
14345a6332275c
1518430120511e
hexc359e9eff9e

13424434020254 has 8 divisors (see below), whose sum is σ = 20144224054920. Its totient is φ = 6709692668616.

The previous prime is 13424434020253. The next prime is 13424434020311. The reversal of 13424434020254 is 45202043442431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×134244340202543 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13424434020251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1262164109 + ... + 1262174744.

It is an arithmetic number, because the mean of its divisors is an integer number (2518028006865).

Almost surely, 213424434020254 is an apocalyptic number.

13424434020254 is a deficient number, since it is larger than the sum of its proper divisors (6719790034666).

13424434020254 is a wasteful number, since it uses less digits than its factorization.

13424434020254 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2524341514.

The product of its (nonzero) digits is 368640, while the sum is 38.

Adding to 13424434020254 its reverse (45202043442431), we get a palindrome (58626477462685).

The spelling of 13424434020254 in words is "thirteen trillion, four hundred twenty-four billion, four hundred thirty-four million, twenty thousand, two hundred fifty-four".

Divisors: 1 2 2659 5318 2524338853 5048677706 6712217010127 13424434020254