Base | Representation |
---|---|
bin | 10011100010010000000… |
… | …011000000010001111010 |
3 | 11202100002101221012222010 |
4 | 103202100003000101322 |
5 | 133443312301044114 |
6 | 2504413355310350 |
7 | 165663035000160 |
oct | 23422003002172 |
9 | 4670071835863 |
10 | 1342446503034 |
11 | 47836806516a |
12 | 19821274b3b6 |
13 | 99790c98120 |
14 | 48d90a3d230 |
15 | 24dc05bbc59 |
hex | 138900c047a |
1342446503034 has 32 divisors (see below), whose sum is σ = 3304483701120. Its totient is φ = 354051824832.
The previous prime is 1342446503017. The next prime is 1342446503053. The reversal of 1342446503034 is 4303056442431.
It is a super-2 number, since 2×13424465030342 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1342446502983 and 1342446503001.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1229346069 + ... + 1229347160.
It is an arithmetic number, because the mean of its divisors is an integer number (103265115660).
Almost surely, 21342446503034 is an apocalyptic number.
1342446503034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
1342446503034 is an abundant number, since it is smaller than the sum of its proper divisors (1962037198086).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1342446503034 is a wasteful number, since it uses less digits than its factorization.
1342446503034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2458693254.
The product of its (nonzero) digits is 414720, while the sum is 39.
The spelling of 1342446503034 in words is "one trillion, three hundred forty-two billion, four hundred forty-six million, five hundred three thousand, thirty-four".
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