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134245025104342 = 2148345261303137
BaseRepresentation
bin11110100001100001011011…
…000010001100000111010110
3122121022200212121122221221111
4132201201123002030013112
5120043432302411314332
61153303151350205234
740163611603555435
oct3641413302140726
9577280777587844
10134245025104342
1139857aa4a02329
121308170335381a
1359ba336860759
1425216cb30511c
15107c04b724947
hex7a185b08c1d6

134245025104342 has 8 divisors (see below), whose sum is σ = 201503321570376. Its totient is φ = 67077251247552.

The previous prime is 134245025104279. The next prime is 134245025104363. The reversal of 134245025104342 is 243401520542431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 134245025104295 and 134245025104304.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22630648603 + ... + 22630654534.

It is an arithmetic number, because the mean of its divisors is an integer number (25187915196297).

Almost surely, 2134245025104342 is an apocalyptic number.

134245025104342 is a deficient number, since it is larger than the sum of its proper divisors (67258296466034).

134245025104342 is a wasteful number, since it uses less digits than its factorization.

134245025104342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45261304622.

The product of its (nonzero) digits is 460800, while the sum is 40.

Adding to 134245025104342 its reverse (243401520542431), we get a palindrome (377646545646773).

The spelling of 134245025104342 in words is "one hundred thirty-four trillion, two hundred forty-five billion, twenty-five million, one hundred four thousand, three hundred forty-two".

Divisors: 1 2 1483 2966 45261303137 90522606274 67122512552171 134245025104342