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13424503012099 is a prime number
BaseRepresentation
bin1100001101011010001010…
…1110111011101100000011
31202112100222200210212211221
43003112202232323230003
53224421340232341344
644315044225215511
72553613461563434
oct303264256735403
952470880725757
1013424503012099
114306332a79813
121609912a91597
13764c04890b8a
14345a6c56148b
151843072d2184
hexc35a2bbbb03

13424503012099 has 2 divisors, whose sum is σ = 13424503012100. Its totient is φ = 13424503012098.

The previous prime is 13424503012087. The next prime is 13424503012163. The reversal of 13424503012099 is 99021030542431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13424503012099 - 237 = 13287064058627 is a prime.

It is a super-2 number, since 2×134245030120992 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13424503018099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712251506049 + 6712251506050.

It is an arithmetic number, because the mean of its divisors is an integer number (6712251506050).

Almost surely, 213424503012099 is an apocalyptic number.

13424503012099 is a deficient number, since it is larger than the sum of its proper divisors (1).

13424503012099 is an equidigital number, since it uses as much as digits as its factorization.

13424503012099 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 43.

The spelling of 13424503012099 in words is "thirteen trillion, four hundred twenty-four billion, five hundred three million, twelve thousand, ninety-nine".