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1342461033053 = 7191780147579
BaseRepresentation
bin10011100010010000111…
…010011011101001011101
311202100010102021102101222
4103202100322123221131
5133443330011024203
62504415034543125
7165663302334560
oct23422072335135
94670112242358
101342461033053
11478375289848
12198217597aa5
1399793cb487a
1448d929424d7
1524dc19dc038
hex13890e9ba5d

1342461033053 has 4 divisors (see below), whose sum is σ = 1534241180640. Its totient is φ = 1150680885468.

The previous prime is 1342461033049. The next prime is 1342461033077. The reversal of 1342461033053 is 3503301642431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1342461033053 - 22 = 1342461033049 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1342461033083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95890073783 + ... + 95890073796.

It is an arithmetic number, because the mean of its divisors is an integer number (383560295160).

Almost surely, 21342461033053 is an apocalyptic number.

It is an amenable number.

1342461033053 is a deficient number, since it is larger than the sum of its proper divisors (191780147587).

1342461033053 is an equidigital number, since it uses as much as digits as its factorization.

1342461033053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191780147586.

The product of its (nonzero) digits is 77760, while the sum is 35.

Adding to 1342461033053 its reverse (3503301642431), we get a palindrome (4845762675484).

The spelling of 1342461033053 in words is "one trillion, three hundred forty-two billion, four hundred sixty-one million, thirty-three thousand, fifty-three".

Divisors: 1 7 191780147579 1342461033053