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1342521034343 = 8339894054889
BaseRepresentation
bin10011100010010100011…
…111010100011001100111
311202100021121011210200222
4103202110133110121213
5133443440341044333
62504425020554555
7165664631335466
oct23422437243147
94670247153628
101342521034343
114783a6140695
121982336b2a5b
13997a35622a8
1448d9a8c09dd
1524dc6de0298
hex138947d4667

1342521034343 has 8 divisors (see below), whose sum is σ = 1359036932400. Its totient is φ = 1326013254208.

The previous prime is 1342521034321. The next prime is 1342521034363. The reversal of 1342521034343 is 3434301252431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1342521034343 - 210 = 1342521033319 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1342521034363) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1696358 + ... + 2358531.

It is an arithmetic number, because the mean of its divisors is an integer number (169879616550).

Almost surely, 21342521034343 is an apocalyptic number.

1342521034343 is a deficient number, since it is larger than the sum of its proper divisors (16515898057).

1342521034343 is an equidigital number, since it uses as much as digits as its factorization.

1342521034343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4058961.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 1342521034343 its reverse (3434301252431), we get a palindrome (4776822286774).

The spelling of 1342521034343 in words is "one trillion, three hundred forty-two billion, five hundred twenty-one million, thirty-four thousand, three hundred forty-three".

Divisors: 1 83 3989 331087 4054889 336555787 16174952221 1342521034343