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134252141252431 is a prime number
BaseRepresentation
bin11110100001101000000011…
…001100001000111101001111
3122121100101020112221201221211
4132201220003030020331033
5120044041341130034211
61153310325434035251
740164253133044036
oct3641500314107517
9577311215851854
10134252141252431
1139860016877754
1213082b6a578b27
1359babcbc42277
142521ba445771d
15107c316332e21
hex7a1a03308f4f

134252141252431 has 2 divisors, whose sum is σ = 134252141252432. Its totient is φ = 134252141252430.

The previous prime is 134252141252417. The next prime is 134252141252441.

134252141252431 is nontrivially palindromic in base 10.

It is a strong prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 134252141252431 - 25 = 134252141252399 is a prime.

It is a super-2 number, since 2×1342521412524312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134252141252441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67126070626215 + 67126070626216.

It is an arithmetic number, because the mean of its divisors is an integer number (67126070626216).

Almost surely, 2134252141252431 is an apocalyptic number.

134252141252431 is a deficient number, since it is larger than the sum of its proper divisors (1).

134252141252431 is an equidigital number, since it uses as much as digits as its factorization.

134252141252431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 230400, while the sum is 40.

The spelling of 134252141252431 in words is "one hundred thirty-four trillion, two hundred fifty-two billion, one hundred forty-one million, two hundred fifty-two thousand, four hundred thirty-one".