Base | Representation |
---|---|
bin | 1100001101011100111101… |
… | …1101011111001010110011 |
3 | 1202112102220222211020010110 |
4 | 3003113033131133022303 |
5 | 3224424404333213210 |
6 | 44315250513032403 |
7 | 2553641203103664 |
oct | 303271735371263 |
9 | 52472828736113 |
10 | 13425253413555 |
11 | 4306688613505 |
12 | 1609aa2255703 |
13 | 764cc41992c9 |
14 | 345b0009936b |
15 | 18434d10d420 |
hex | c35cf75f2b3 |
13425253413555 has 8 divisors (see below), whose sum is σ = 21480405461712. Its totient is φ = 7160135153888.
The previous prime is 13425253413497. The next prime is 13425253413571. The reversal of 13425253413555 is 55531435252431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13425253413555 - 228 = 13424984978099 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 447508447104 + ... + 447508447133.
It is an arithmetic number, because the mean of its divisors is an integer number (2685050682714).
Almost surely, 213425253413555 is an apocalyptic number.
13425253413555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13425253413555 is a deficient number, since it is larger than the sum of its proper divisors (8055152048157).
13425253413555 is an equidigital number, since it uses as much as digits as its factorization.
13425253413555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 895016894245.
The product of its digits is 5400000, while the sum is 48.
Adding to 13425253413555 its reverse (55531435252431), we get a palindrome (68956688665986).
The spelling of 13425253413555 in words is "thirteen trillion, four hundred twenty-five billion, two hundred fifty-three million, four hundred thirteen thousand, five hundred fifty-five".
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