Base | Representation |
---|---|
bin | 11001000000011011… |
… | …11010100010001111 |
3 | 1021122122022000120202 |
4 | 30200031322202033 |
5 | 204443401423211 |
6 | 10100105204115 |
7 | 653460122303 |
oct | 144015724217 |
9 | 37578260522 |
10 | 13425420431 |
11 | 576a333095 |
12 | 272819063b |
13 | 135c573977 |
14 | 915069d03 |
15 | 53898753b |
hex | 32037a88f |
13425420431 has 2 divisors, whose sum is σ = 13425420432. Its totient is φ = 13425420430.
The previous prime is 13425420383. The next prime is 13425420443. The reversal of 13425420431 is 13402452431.
It is a strong prime.
It is an emirp because it is prime and its reverse (13402452431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13425420431 - 210 = 13425419407 is a prime.
It is a super-2 number, since 2×134254204312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13425420394 and 13425420403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13425420451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712710215 + 6712710216.
It is an arithmetic number, because the mean of its divisors is an integer number (6712710216).
Almost surely, 213425420431 is an apocalyptic number.
13425420431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425420431 is an equidigital number, since it uses as much as digits as its factorization.
13425420431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 13425420431 its reverse (13402452431), we get a palindrome (26827872862).
The spelling of 13425420431 in words is "thirteen billion, four hundred twenty-five million, four hundred twenty thousand, four hundred thirty-one".
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