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13425420431 is a prime number
BaseRepresentation
bin11001000000011011…
…11010100010001111
31021122122022000120202
430200031322202033
5204443401423211
610100105204115
7653460122303
oct144015724217
937578260522
1013425420431
11576a333095
12272819063b
13135c573977
14915069d03
1553898753b
hex32037a88f

13425420431 has 2 divisors, whose sum is σ = 13425420432. Its totient is φ = 13425420430.

The previous prime is 13425420383. The next prime is 13425420443. The reversal of 13425420431 is 13402452431.

It is a strong prime.

It is an emirp because it is prime and its reverse (13402452431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13425420431 - 210 = 13425419407 is a prime.

It is a super-2 number, since 2×134254204312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13425420394 and 13425420403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13425420451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712710215 + 6712710216.

It is an arithmetic number, because the mean of its divisors is an integer number (6712710216).

Almost surely, 213425420431 is an apocalyptic number.

13425420431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13425420431 is an equidigital number, since it uses as much as digits as its factorization.

13425420431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 13425420431 its reverse (13402452431), we get a palindrome (26827872862).

The spelling of 13425420431 in words is "thirteen billion, four hundred twenty-five million, four hundred twenty thousand, four hundred thirty-one".