Base | Representation |
---|---|
bin | 1100001101011101100110… |
… | …1000111111100110010011 |
3 | 1202112110100220012012000021 |
4 | 3003113121220333212103 |
5 | 3224430232043432011 |
6 | 44315315453404311 |
7 | 2553645345555604 |
oct | 303273150774623 |
9 | 52473326165007 |
10 | 13425424202131 |
11 | 4306765a64497 |
12 | 1609b2b499697 |
13 | 765020696536 |
14 | 345b18a35dab |
15 | 18435d0e7471 |
hex | c35d9a3f993 |
13425424202131 has 2 divisors, whose sum is σ = 13425424202132. Its totient is φ = 13425424202130.
The previous prime is 13425424202129. The next prime is 13425424202137. The reversal of 13425424202131 is 13120242452431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13425424202131 - 21 = 13425424202129 is a prime.
It is a super-2 number, since 2×134254242021312 (a number of 27 digits) contains 22 as substring.
Together with 13425424202129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13425424202137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712712101065 + 6712712101066.
It is an arithmetic number, because the mean of its divisors is an integer number (6712712101066).
Almost surely, 213425424202131 is an apocalyptic number.
13425424202131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425424202131 is an equidigital number, since it uses as much as digits as its factorization.
13425424202131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 13425424202131 its reverse (13120242452431), we get a palindrome (26545666654562).
The spelling of 13425424202131 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-four million, two hundred two thousand, one hundred thirty-one".
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