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13425425420443 is a prime number
BaseRepresentation
bin1100001101011101100110…
…1101101001000010011011
31202112110100222111002012221
43003113121231221002123
53224430232401423233
644315315535444511
72553645362121541
oct303273155510233
952473328432187
1013425425420443
114306766716863
121609b2b986737
13765020a01c2a
14345b18c71d91
1518435d28842d
hexc35d9b6909b

13425425420443 has 2 divisors, whose sum is σ = 13425425420444. Its totient is φ = 13425425420442.

The previous prime is 13425425420413. The next prime is 13425425420447. The reversal of 13425425420443 is 34402452452431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13425425420443 - 241 = 11226402164891 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13425425420443.

It is not a weakly prime, because it can be changed into another prime (13425425420447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712712710221 + 6712712710222.

It is an arithmetic number, because the mean of its divisors is an integer number (6712712710222).

Almost surely, 213425425420443 is an apocalyptic number.

13425425420443 is a deficient number, since it is larger than the sum of its proper divisors (1).

13425425420443 is an equidigital number, since it uses as much as digits as its factorization.

13425425420443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1843200, while the sum is 43.

Adding to 13425425420443 its reverse (34402452452431), we get a palindrome (47827877872874).

The spelling of 13425425420443 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-five million, four hundred twenty thousand, four hundred forty-three".