Base | Representation |
---|---|
bin | 1100001101011101100110… |
… | …1101110001000010110111 |
3 | 1202112110100222112202012121 |
4 | 3003113121231301002313 |
5 | 3224430232404000424 |
6 | 44315315540300411 |
7 | 2553645362316262 |
oct | 303273155610267 |
9 | 52473328482177 |
10 | 13425425453239 |
11 | 4306766739468 |
12 | 1609b2b9a1707 |
13 | 765020a13b37 |
14 | 345b18c7dcd9 |
15 | 18435d292ee4 |
hex | c35d9b710b7 |
13425425453239 has 2 divisors, whose sum is σ = 13425425453240. Its totient is φ = 13425425453238.
The previous prime is 13425425453171. The next prime is 13425425453257. The reversal of 13425425453239 is 93235452452431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13425425453239 - 29 = 13425425452727 is a prime.
It is a super-2 number, since 2×134254254532392 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13425425456239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712712726619 + 6712712726620.
It is an arithmetic number, because the mean of its divisors is an integer number (6712712726620).
Almost surely, 213425425453239 is an apocalyptic number.
13425425453239 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425425453239 is an equidigital number, since it uses as much as digits as its factorization.
13425425453239 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15552000, while the sum is 52.
The spelling of 13425425453239 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-five million, four hundred fifty-three thousand, two hundred thirty-nine".
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