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13425541213151 = 41327452224711
BaseRepresentation
bin1100001101011110000010…
…0111010110101111011111
31202112110200001100221221202
43003113200213112233133
53224431002022310101
644315335233350115
72553651266260604
oct303274047265737
952473601327852
1013425541213151
114306816014611
121609b6270833b
1376503b9b4b22
14345b2a3b46ab
1518436850c36b
hexc35e09d6bdf

13425541213151 has 4 divisors (see below), whose sum is σ = 13752993437904. Its totient is φ = 13098088988400.

The previous prime is 13425541213141. The next prime is 13425541213169. The reversal of 13425541213151 is 15131214552431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13425541213151 - 222 = 13425537018847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13425541213141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163726112315 + ... + 163726112396.

It is an arithmetic number, because the mean of its divisors is an integer number (3438248359476).

Almost surely, 213425541213151 is an apocalyptic number.

13425541213151 is a deficient number, since it is larger than the sum of its proper divisors (327452224753).

13425541213151 is an equidigital number, since it uses as much as digits as its factorization.

13425541213151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 327452224752.

The product of its digits is 72000, while the sum is 38.

Adding to 13425541213151 its reverse (15131214552431), we get a palindrome (28556755765582).

The spelling of 13425541213151 in words is "thirteen trillion, four hundred twenty-five billion, five hundred forty-one million, two hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 41 327452224711 13425541213151