Base | Representation |
---|---|
bin | 1100001101011110000010… |
… | …0111010110101111011111 |
3 | 1202112110200001100221221202 |
4 | 3003113200213112233133 |
5 | 3224431002022310101 |
6 | 44315335233350115 |
7 | 2553651266260604 |
oct | 303274047265737 |
9 | 52473601327852 |
10 | 13425541213151 |
11 | 4306816014611 |
12 | 1609b6270833b |
13 | 76503b9b4b22 |
14 | 345b2a3b46ab |
15 | 18436850c36b |
hex | c35e09d6bdf |
13425541213151 has 4 divisors (see below), whose sum is σ = 13752993437904. Its totient is φ = 13098088988400.
The previous prime is 13425541213141. The next prime is 13425541213169. The reversal of 13425541213151 is 15131214552431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13425541213151 - 222 = 13425537018847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13425541213141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163726112315 + ... + 163726112396.
It is an arithmetic number, because the mean of its divisors is an integer number (3438248359476).
Almost surely, 213425541213151 is an apocalyptic number.
13425541213151 is a deficient number, since it is larger than the sum of its proper divisors (327452224753).
13425541213151 is an equidigital number, since it uses as much as digits as its factorization.
13425541213151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 327452224752.
The product of its digits is 72000, while the sum is 38.
Adding to 13425541213151 its reverse (15131214552431), we get a palindrome (28556755765582).
The spelling of 13425541213151 in words is "thirteen trillion, four hundred twenty-five billion, five hundred forty-one million, two hundred thirteen thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.133 sec. • engine limits •