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1342630503142 = 210921601285119
BaseRepresentation
bin10011100010011011000…
…000111010001011100110
311202100120020011101122221
4103202123000322023212
5133444201402100032
62504443531142554
7166000430655505
oct23423300721346
94670506141587
101342630503142
11478451a0a175
121982642a4a5a
13997c013c926
1448dab25883c
1524dd1815597
hex1389b03a2e6

1342630503142 has 16 divisors (see below), whose sum is σ = 2032523539200. Its totient is φ = 665123270400.

The previous prime is 1342630503107. The next prime is 1342630503143. The reversal of 1342630503142 is 2413050362431.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 1342630503098 and 1342630503107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1342630503143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4566459 + ... + 4851577.

It is an arithmetic number, because the mean of its divisors is an integer number (127032721200).

Almost surely, 21342630503142 is an apocalyptic number.

1342630503142 is a deficient number, since it is larger than the sum of its proper divisors (689893036058).

1342630503142 is a wasteful number, since it uses less digits than its factorization.

1342630503142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 306831.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 1342630503142 its reverse (2413050362431), we get a palindrome (3755680865573).

The spelling of 1342630503142 in words is "one trillion, three hundred forty-two billion, six hundred thirty million, five hundred three thousand, one hundred forty-two".

Divisors: 1 2 109 218 21601 43202 285119 570238 2354509 4709018 31077971 62155942 6158855519 12317711038 671315251571 1342630503142