Search a number
-
+
134265053655217 is a prime number
BaseRepresentation
bin11110100001110100000100…
…110101000011000010110001
3122121101121120102220202122001
4132201310010311003002301
5120044244312213431332
61153320303015414001
740165221123464152
oct3641640465030261
9577347512822561
10134265053655217
1139865542562011
1213085572984301
1359bc1a91238a4
14252266b2dd929
15107c81ec300e7
hex7a1d04d430b1

134265053655217 has 2 divisors, whose sum is σ = 134265053655218. Its totient is φ = 134265053655216.

The previous prime is 134265053655199. The next prime is 134265053655259. The reversal of 134265053655217 is 712556350562431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100089700106256 + 34175353548961 = 10004484^2 + 5845969^2 .

It is a cyclic number.

It is not a de Polignac number, because 134265053655217 - 235 = 134230693916849 is a prime.

It is a super-2 number, since 2×1342650536552172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (134265053652217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132526827608 + 67132526827609.

It is an arithmetic number, because the mean of its divisors is an integer number (67132526827609).

Almost surely, 2134265053655217 is an apocalyptic number.

It is an amenable number.

134265053655217 is a deficient number, since it is larger than the sum of its proper divisors (1).

134265053655217 is an equidigital number, since it uses as much as digits as its factorization.

134265053655217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22680000, while the sum is 55.

The spelling of 134265053655217 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, fifty-three million, six hundred fifty-five thousand, two hundred seventeen".