Base | Representation |
---|---|
bin | 11110100001110100000100… |
… | …110101000011000011011011 |
3 | 122121101121120102220202200121 |
4 | 132201310010311003003123 |
5 | 120044244312213432014 |
6 | 1153320303015414111 |
7 | 40165221123464242 |
oct | 3641640465030333 |
9 | 577347512822617 |
10 | 134265053655259 |
11 | 3986554256204a |
12 | 13085572984337 |
13 | 59bc1a9123907 |
14 | 252266b2dd959 |
15 | 107c81ec30124 |
hex | 7a1d04d430db |
134265053655259 has 2 divisors, whose sum is σ = 134265053655260. Its totient is φ = 134265053655258.
The previous prime is 134265053655217. The next prime is 134265053655269. The reversal of 134265053655259 is 952556350562431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134265053655259 - 233 = 134256463720667 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134265053655197 and 134265053655206.
It is not a weakly prime, because it can be changed into another prime (134265053655269) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132526827629 + 67132526827630.
It is an arithmetic number, because the mean of its divisors is an integer number (67132526827630).
Almost surely, 2134265053655259 is an apocalyptic number.
134265053655259 is a deficient number, since it is larger than the sum of its proper divisors (1).
134265053655259 is an equidigital number, since it uses as much as digits as its factorization.
134265053655259 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145800000, while the sum is 61.
The spelling of 134265053655259 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, fifty-three million, six hundred fifty-five thousand, two hundred fifty-nine".
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