Base | Representation |
---|---|
bin | 111110100001011011… |
… | …0101011001010110111 |
3 | 110211120012102221101201 |
4 | 1331002312223022313 |
5 | 4144433444140111 |
6 | 141403014033331 |
7 | 12462140616532 |
oct | 1750266531267 |
9 | 424505387351 |
10 | 134265615031 |
11 | 51a3a491909 |
12 | 22031348847 |
13 | c8798451b2 |
14 | 66d9c01a19 |
15 | 375c5a46c1 |
hex | 1f42dab2b7 |
134265615031 has 2 divisors, whose sum is σ = 134265615032. Its totient is φ = 134265615030.
The previous prime is 134265614999. The next prime is 134265615037. The reversal of 134265615031 is 130516562431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134265615031 - 25 = 134265614999 is a prime.
It is a super-2 number, since 2×1342656150312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134265615037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132807515 + 67132807516.
It is an arithmetic number, because the mean of its divisors is an integer number (67132807516).
Almost surely, 2134265615031 is an apocalyptic number.
134265615031 is a deficient number, since it is larger than the sum of its proper divisors (1).
134265615031 is an equidigital number, since it uses as much as digits as its factorization.
134265615031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 134265615031 in words is "one hundred thirty-four billion, two hundred sixty-five million, six hundred fifteen thousand, thirty-one".
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