Base | Representation |
---|---|
bin | 10011100010011110111… |
… | …110110100011011000111 |
3 | 11202100201212102001011220 |
4 | 103202132332310123013 |
5 | 133444320422023020 |
6 | 2504454305531423 |
7 | 166002166510050 |
oct | 23423676643307 |
9 | 4670655361156 |
10 | 1342697064135 |
11 | 478486541459 |
12 | 198282643b73 |
13 | 99800b7602b |
14 | 48db6023727 |
15 | 24dd75b2240 |
hex | 1389efb46c7 |
1342697064135 has 16 divisors (see below), whose sum is σ = 2455217488896. Its totient is φ = 613804372128.
The previous prime is 1342697064133. The next prime is 1342697064161. The reversal of 1342697064135 is 5314607962431.
It is not a de Polignac number, because 1342697064135 - 21 = 1342697064133 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1342697064133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6393795439 + ... + 6393795648.
It is an arithmetic number, because the mean of its divisors is an integer number (153451093056).
Almost surely, 21342697064135 is an apocalyptic number.
1342697064135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1342697064135 is a deficient number, since it is larger than the sum of its proper divisors (1112520424761).
1342697064135 is a wasteful number, since it uses less digits than its factorization.
1342697064135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12787591102.
The product of its (nonzero) digits is 3265920, while the sum is 51.
The spelling of 1342697064135 in words is "one trillion, three hundred forty-two billion, six hundred ninety-seven million, sixty-four thousand, one hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •