Base | Representation |
---|---|
bin | 1100001101101011101101… |
… | …1101001010100011001101 |
3 | 1202112211010221000110111221 |
4 | 3003122323131022203031 |
5 | 3230011011431031302 |
6 | 44321143431243341 |
7 | 2554141260655663 |
oct | 303327335124315 |
9 | 52484127013457 |
10 | 13429212752077 |
11 | 430832a555101 |
12 | 160a808219551 |
13 | 7654a5552075 |
14 | 345d97c66c33 |
15 | 1844d0a00937 |
hex | c36bb74a8cd |
13429212752077 has 2 divisors, whose sum is σ = 13429212752078. Its totient is φ = 13429212752076.
The previous prime is 13429212752057. The next prime is 13429212752143. The reversal of 13429212752077 is 77025721292431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13401354137796 + 27858614281 = 3660786^2 + 166909^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13429212752077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13429212752017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6714606376038 + 6714606376039.
It is an arithmetic number, because the mean of its divisors is an integer number (6714606376039).
Almost surely, 213429212752077 is an apocalyptic number.
It is an amenable number.
13429212752077 is a deficient number, since it is larger than the sum of its proper divisors (1).
13429212752077 is an equidigital number, since it uses as much as digits as its factorization.
13429212752077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2963520, while the sum is 52.
The spelling of 13429212752077 in words is "thirteen trillion, four hundred twenty-nine billion, two hundred twelve million, seven hundred fifty-two thousand, seventy-seven".
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