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134305103100111 = 344768367700037
BaseRepresentation
bin11110100010011001010111…
…111101100011100011001111
3122121112102221120000100202220
4132202121113331203203033
5120100423322343200421
61153350525042150423
740201136441241156
oct3642312775434317
9577472846010686
10134305103100111
11398805244117a9
121309128b352413
1359c2bbc4c8988
14252458a29c59d
15107d8b5c323c6
hex7a2657f638cf

134305103100111 has 4 divisors (see below), whose sum is σ = 179073470800152. Its totient is φ = 89536735400072.

The previous prime is 134305103100059. The next prime is 134305103100139. The reversal of 134305103100111 is 111001301503431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134305103100111 - 213 = 134305103091919 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134305103100151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22384183850016 + ... + 22384183850021.

It is an arithmetic number, because the mean of its divisors is an integer number (44768367700038).

Almost surely, 2134305103100111 is an apocalyptic number.

134305103100111 is a deficient number, since it is larger than the sum of its proper divisors (44768367700041).

134305103100111 is an equidigital number, since it uses as much as digits as its factorization.

134305103100111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44768367700040.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 134305103100111 its reverse (111001301503431), we get a palindrome (245306404603542).

The spelling of 134305103100111 in words is "one hundred thirty-four trillion, three hundred five billion, one hundred three million, one hundred thousand, one hundred eleven".

Divisors: 1 3 44768367700037 134305103100111