Base | Representation |
---|---|
bin | 11110100010011001010111… |
… | …111101100011100011001111 |
3 | 122121112102221120000100202220 |
4 | 132202121113331203203033 |
5 | 120100423322343200421 |
6 | 1153350525042150423 |
7 | 40201136441241156 |
oct | 3642312775434317 |
9 | 577472846010686 |
10 | 134305103100111 |
11 | 398805244117a9 |
12 | 1309128b352413 |
13 | 59c2bbc4c8988 |
14 | 252458a29c59d |
15 | 107d8b5c323c6 |
hex | 7a2657f638cf |
134305103100111 has 4 divisors (see below), whose sum is σ = 179073470800152. Its totient is φ = 89536735400072.
The previous prime is 134305103100059. The next prime is 134305103100139. The reversal of 134305103100111 is 111001301503431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134305103100111 - 213 = 134305103091919 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134305103100151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22384183850016 + ... + 22384183850021.
It is an arithmetic number, because the mean of its divisors is an integer number (44768367700038).
Almost surely, 2134305103100111 is an apocalyptic number.
134305103100111 is a deficient number, since it is larger than the sum of its proper divisors (44768367700041).
134305103100111 is an equidigital number, since it uses as much as digits as its factorization.
134305103100111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44768367700040.
The product of its (nonzero) digits is 540, while the sum is 24.
Adding to 134305103100111 its reverse (111001301503431), we get a palindrome (245306404603542).
The spelling of 134305103100111 in words is "one hundred thirty-four trillion, three hundred five billion, one hundred three million, one hundred thousand, one hundred eleven".
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