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13431013052467 is a prime number
BaseRepresentation
bin1100001101110010011011…
…0000110001000000110011
31202112222210101121012101011
43003130212300301000303
53230023203320134332
644322042222051351
72554234011164113
oct303344660610063
952488711535334
1013431013052467
1143090737a446a
12160b02b119b57
13765701518a7a
143460c8dbb043
15184588ab7e47
hexc3726c31033

13431013052467 has 2 divisors, whose sum is σ = 13431013052468. Its totient is φ = 13431013052466.

The previous prime is 13431013052441. The next prime is 13431013052519. The reversal of 13431013052467 is 76425031013431.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (76425031013431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13431013052467 - 211 = 13431013050419 is a prime.

It is a super-2 number, since 2×134310130524672 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13431013052417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715506526233 + 6715506526234.

It is an arithmetic number, because the mean of its divisors is an integer number (6715506526234).

Almost surely, 213431013052467 is an apocalyptic number.

13431013052467 is a deficient number, since it is larger than the sum of its proper divisors (1).

13431013052467 is an equidigital number, since it uses as much as digits as its factorization.

13431013052467 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 40.

Adding to 13431013052467 its reverse (76425031013431), we get a palindrome (89856044065898).

The spelling of 13431013052467 in words is "thirteen trillion, four hundred thirty-one billion, thirteen million, fifty-two thousand, four hundred sixty-seven".