Base | Representation |
---|---|
bin | 111110100010110001… |
… | …1011010000011101101 |
3 | 110211200100122110000012 |
4 | 1331011203122003231 |
5 | 4200032042131403 |
6 | 141411312343005 |
7 | 12463230530561 |
oct | 1750543320355 |
9 | 424610573005 |
10 | 134310895853 |
11 | 51a62aa9a82 |
12 | 22044544a65 |
13 | c88603a594 |
14 | 6701c2b6a1 |
15 | 376154aed8 |
hex | 1f458da0ed |
134310895853 has 2 divisors, whose sum is σ = 134310895854. Its totient is φ = 134310895852.
The previous prime is 134310895837. The next prime is 134310895909. The reversal of 134310895853 is 358598013431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109737825289 + 24573070564 = 331267^2 + 156758^2 .
It is a cyclic number.
It is not a de Polignac number, because 134310895853 - 24 = 134310895837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134310895813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67155447926 + 67155447927.
It is an arithmetic number, because the mean of its divisors is an integer number (67155447927).
Almost surely, 2134310895853 is an apocalyptic number.
It is an amenable number.
134310895853 is a deficient number, since it is larger than the sum of its proper divisors (1).
134310895853 is an equidigital number, since it uses as much as digits as its factorization.
134310895853 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1555200, while the sum is 50.
The spelling of 134310895853 in words is "one hundred thirty-four billion, three hundred ten million, eight hundred ninety-five thousand, eight hundred fifty-three".
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