134311221131 has 2 divisors, whose sum is σ = 134311221132. Its totient is φ = 134311221130.

The previous prime is 134311221113. The next prime is 134311221157. The reversal of 134311221131 is 131122113431.

Together with previous prime (134311221113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134311221131 is a prime.

It is a super-2 number, since 2×134311221131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134311221097 and 134311221106.

It is not a weakly prime, because it can be changed into another prime (134311227131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67155610565 + 67155610566.

It is an arithmetic number, because the mean of its divisors is an integer number (67155610566).

Almost surely, 2^134311221131 is an apocalyptic number.

134311221131 is a deficient number, since it is larger than the sum of its proper divisors (1).

134311221131 is an equidigital number, since it uses as much as digits as its factorization.

134311221131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 432, while the sum is 23.

Adding to 134311221131 its reverse (131122113431), we get a palindrome (265433334562).

It can be divided in two parts, 13431 and 1221131, that multiplied together give a palindrome (16401010461).

The spelling of 134311221131 in words is "one hundred thirty-four billion, three hundred eleven million, two hundred twenty-one thousand, one hundred thirty-one".