Base | Representation |
---|---|
bin | 11110100010011111000100… |
… | …101011101111111101000011 |
3 | 122121120000202000000120210001 |
4 | 132202133010223233331003 |
5 | 120101023340330204123 |
6 | 1153353420150020431 |
7 | 40201444202102131 |
oct | 3642370453577503 |
9 | 577500660016701 |
10 | 134311222116163 |
11 | 39883084442064 |
12 | 130924b8647717 |
13 | 59c3656135831 |
14 | 25249aac0c751 |
15 | 107db230290ad |
hex | 7a27c4aeff43 |
134311222116163 has 2 divisors, whose sum is σ = 134311222116164. Its totient is φ = 134311222116162.
The previous prime is 134311222116151. The next prime is 134311222116173. The reversal of 134311222116163 is 361611222113431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134311222116163 - 25 = 134311222116131 is a prime.
It is not a weakly prime, because it can be changed into another prime (134311222116173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67155611058081 + 67155611058082.
It is an arithmetic number, because the mean of its divisors is an integer number (67155611058082).
Almost surely, 2134311222116163 is an apocalyptic number.
134311222116163 is a deficient number, since it is larger than the sum of its proper divisors (1).
134311222116163 is an equidigital number, since it uses as much as digits as its factorization.
134311222116163 is an evil number, because the sum of its binary digits is even.
The product of its digits is 31104, while the sum is 37.
Adding to 134311222116163 its reverse (361611222113431), we get a palindrome (495922444229594).
The spelling of 134311222116163 in words is "one hundred thirty-four trillion, three hundred eleven billion, two hundred twenty-two million, one hundred sixteen thousand, one hundred sixty-three".
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