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1343112433103 = 7191873204729
BaseRepresentation
bin10011100010110111101…
…111010100110111001111
311202101210210222222021202
4103202313233110313033
5134001143240324403
62505003424420115
7166015402212230
oct23426757246717
94671723888252
101343112433103
11478679a542a1
1219837977763b
1399868c38b9c
1449015269087
1524e0dcae688
hex138b7bd4dcf

1343112433103 has 4 divisors (see below), whose sum is σ = 1534985637840. Its totient is φ = 1151239228368.

The previous prime is 1343112433097. The next prime is 1343112433111. The reversal of 1343112433103 is 3013342113431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1343112433103 - 216 = 1343112367567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1343112433163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95936602358 + ... + 95936602371.

It is an arithmetic number, because the mean of its divisors is an integer number (383746409460).

Almost surely, 21343112433103 is an apocalyptic number.

1343112433103 is a deficient number, since it is larger than the sum of its proper divisors (191873204737).

1343112433103 is an equidigital number, since it uses as much as digits as its factorization.

1343112433103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 191873204736.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1343112433103 its reverse (3013342113431), we get a palindrome (4356454546534).

The spelling of 1343112433103 in words is "one trillion, three hundred forty-three billion, one hundred twelve million, four hundred thirty-three thousand, one hundred three".

Divisors: 1 7 191873204729 1343112433103