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13431127 is a prime number
BaseRepresentation
bin110011001111…
…000101010111
3221021101001011
4303033011113
511414244002
61155513051
7222106543
oct63170527
927241034
1013431127
117644006
1245b8787
132a23518
141ad8a23
1512a48d7
hexccf157

13431127 has 2 divisors, whose sum is σ = 13431128. Its totient is φ = 13431126.

The previous prime is 13431113. The next prime is 13431133. The reversal of 13431127 is 72113431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13431127 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13431098 and 13431107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13431137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715563 + 6715564.

It is an arithmetic number, because the mean of its divisors is an integer number (6715564).

Almost surely, 213431127 is an apocalyptic number.

13431127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13431127 is an equidigital number, since it uses as much as digits as its factorization.

13431127 is an evil number, because the sum of its binary digits is even.

The product of its digits is 504, while the sum is 22.

The square root of 13431127 is about 3664.8502015771. The cubic root of 13431127 is about 237.7045447474.

Adding to 13431127 its reverse (72113431), we get a palindrome (85544558).

The spelling of 13431127 in words is "thirteen million, four hundred thirty-one thousand, one hundred twenty-seven".