Base | Representation |
---|---|
bin | 111110100010110010… |
… | …1011010000100010101 |
3 | 110211200101122002020202 |
4 | 1331011211122010111 |
5 | 4200032210421211 |
6 | 141411331510245 |
7 | 12463235143331 |
oct | 1750545320425 |
9 | 424611562222 |
10 | 134311420181 |
11 | 51a63327a04 |
12 | 22044758385 |
13 | c886192133 |
14 | 6701d267c1 |
15 | 376160153b |
hex | 1f4595a115 |
134311420181 has 2 divisors, whose sum is σ = 134311420182. Its totient is φ = 134311420180.
The previous prime is 134311420129. The next prime is 134311420189. The reversal of 134311420181 is 181024113431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79149382225 + 55162037956 = 281335^2 + 234866^2 .
It is a cyclic number.
It is not a de Polignac number, because 134311420181 - 226 = 134244311317 is a prime.
It is a super-2 number, since 2×1343114201812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134311420189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67155710090 + 67155710091.
It is an arithmetic number, because the mean of its divisors is an integer number (67155710091).
Almost surely, 2134311420181 is an apocalyptic number.
It is an amenable number.
134311420181 is a deficient number, since it is larger than the sum of its proper divisors (1).
134311420181 is an equidigital number, since it uses as much as digits as its factorization.
134311420181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 29.
The spelling of 134311420181 in words is "one hundred thirty-four billion, three hundred eleven million, four hundred twenty thousand, one hundred eighty-one".
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